Hey Guys
My girlfriends dad is talking about the Brazillian Lottery. Over here you can do the usual 6 numbers (their range is 1-60) for 2 reais, or you can do 7 numbers for 14reais, or 8 numbers for 56reais up to a maximum of 15numbers for 10010reais. As the new years eve jackpot is going to be 170million, 139people from his work have put in 100reais each giving 13900reais to buy tickets. So now he's wondering is it better to buy 1x 15numbers and 1945x 6numbers, or just buy 13900 worth of 6numbers. I tried to work out the odds but I'm working it out that its 3times better to do 1x 15 and 1945x 6 than 6950x 6 but I don't think thats right.
The odds of picking the 6 number combination that wins the lottery is 50,063,860 to 1 which at a cost of 2reais each means its 100,127,720reais to be guaranteed to win the lottery.
With 10number combinations it is 238,399.33 to 1 which at a cost of 420reais each means it costs the same 100,127,720reais to be guaranteed to win.
Again with 15numbers it is 10002.7692 to 1 and at a cost of 10010reais mess its the same 100,127,720reais
So to me the odds of just winning should be exactly the same whatever way you spend the 13900. Am I correct? I love probability but this one is stumping me as to how to go about it
Thanks for the help!
My girlfriends dad is talking about the Brazillian Lottery. Over here you can do the usual 6 numbers (their range is 1-60) for 2 reais, or you can do 7 numbers for 14reais, or 8 numbers for 56reais up to a maximum of 15numbers for 10010reais. As the new years eve jackpot is going to be 170million, 139people from his work have put in 100reais each giving 13900reais to buy tickets. So now he's wondering is it better to buy 1x 15numbers and 1945x 6numbers, or just buy 13900 worth of 6numbers. I tried to work out the odds but I'm working it out that its 3times better to do 1x 15 and 1945x 6 than 6950x 6 but I don't think thats right.
The odds of picking the 6 number combination that wins the lottery is 50,063,860 to 1 which at a cost of 2reais each means its 100,127,720reais to be guaranteed to win the lottery.
With 10number combinations it is 238,399.33 to 1 which at a cost of 420reais each means it costs the same 100,127,720reais to be guaranteed to win.
Again with 15numbers it is 10002.7692 to 1 and at a cost of 10010reais mess its the same 100,127,720reais
So to me the odds of just winning should be exactly the same whatever way you spend the 13900. Am I correct? I love probability but this one is stumping me as to how to go about it
Thanks for the help!
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